MathLabs

Problem 3

Consider all triangles ABCABC with a fixed base ABAB and whose altitude from CC is a constant hh. For which of these triangles is the product of its three altitudes a maximum?
Step 1 of 5: Multiply the three area identities
AB⋅h⋅AC⋅hb⋅BC⋅ha=8[ABC]3=(AB⋅h)3AB\cdot h\cdot AC\cdot h_b\cdot BC\cdot h_a=8[ABC]^3=(AB\cdot h)^3
Detailed analysis

Let ha,hbh_a,h_b be the altitudes from A,BA,B. The equal area expressions are AB⋅h=AC⋅hb=BC⋅ha=2[ABC]AB\cdot h=AC\cdot h_b=BC\cdot h_a=2[ABC]. Multiplying them gives the displayed identity. Since ABAB and hh are fixed, its right side is constant.