MathLabs

Problem 3

Consider all triangles ABCABC with a fixed base ABAB and whose altitude from CC is a constant hh. For which of these triangles is the product of its three altitudes a maximum?
Step 3 of 5: Express the side product using sin C
(sin⁡C)AC⋅BC=BC⋅ha=2[ABC](\sin C)AC\cdot BC=BC\cdot h_a=2[ABC]
Detailed analysis

The area formula using the two sides adjacent to CC gives [ABC]=12AC⋅BCsin⁡C[ABC]=\tfrac12 AC\cdot BC\sin C. Equivalently, (sin⁡C)AC⋅BC=2[ABC]=BC⋅ha(\sin C)AC\cdot BC=2[ABC]=BC\cdot h_a, which is constant because the area is fixed. Therefore AC⋅BCAC\cdot BC is minimized exactly when sin⁡C\sin C is maximized.