Problem 5
Show that for every integer n>=6 there exists a convex hexagon that can be dissected into exactly n congruent triangles.
Step 2 of 4: Obtain three arithmetic families
Detailed analysis
With p=q=1, the block counts in the official diagrams are 4n+2 for L_1+nM+R_1, 4n+5 for L_1+nM+R_2, and 4n+6 for L_2+nM+R_2. The stated lower bounds on n make each resulting boundary a convex hexagon.