MathLabs

Problem 3

Let n>3n>3 be an integer. Choose three numbers from {1,2,…,n}\{1,2,\ldots,n\}. Using each once, together with addition, multiplication, and parentheses, form all possible combinations. (a) Show that if all three chosen numbers are greater than n/2n/2, their values are all distinct. (b) Let pp be a prime with p≤np\le \sqrt{n}. Show that the number of choices whose smallest number is pp and whose combination values are not all distinct is exactly the number of positive divisors of p−1p-1.
Step 3 of 7: Compare the two chains
(y+z)x−(y+zx)=(x−1)y>0,(x+z)y−(x+yz)=(y−1)x>0(y+z)x-(y+zx)=(x-1)y>0,\qquad (x+z)y-(x+yz)=(y-1)x>0
Detailed analysis

The first inequality places (y+z)x(y+z)x above y+zxy+zx, and the second places (x+z)y(x+z)y above x+yzx+yz. Therefore every cross-comparison is settled except possibly x+yzx+yz versus (y+z)x(y+z)x; all other values are strictly ordered.