MathLabs

Problem 3

Let f(x)=anxn+an−1xn−1+⋯+a0f(x)=a_nx^n+a_{n-1}x^{n-1}+\cdots+a_0 and g(x)=cn+1xn+1+cnxn+⋯+c0g(x)=c_{n+1}x^{n+1}+c_nx^n+\cdots+c_0 be non-zero real polynomials such that g(x)=(x+r)f(x)g(x)=(x+r)f(x) for some real rr. If a=max⁡(∣an∣,…,∣a0∣)a=\max(|a_n|,\ldots,|a_0|) and c=max⁡(∣cn+1∣,…,∣c0∣)c=\max(|c_{n+1}|,\ldots,|c_0|), prove that ac≤n+1\frac{a}{c}\le n+1.
Step 1 of 5: Expand the product and record coefficient recurrences
cn+1=an,ck=ak−1+rak (1≤k≤n),c0=ra0c_{n+1}=a_n,\qquad c_k=a_{k-1}+ra_k\ (1\le k\le n),\qquad c_0=ra_0
Detailed analysis

Comparing coefficients in g(x)=(x+r)f(x)g(x)=(x+r)f(x) gives cn+1=anc_{n+1}=a_n, ck=ak−1+rakc_k=a_{k-1}+ra_k for 1≤k≤n1\le k\le n, and c0=ra0c_0=ra_0. By definition every coefficient of gg has absolute value at most cc.