MathLabs

Problem 1

Determine all sequences of real numbers (a1,a2,…,a1995)(a_1,a_2,\ldots,a_{1995}) satisfying 2an−(n−1)≥an+1−(n−1)2\sqrt{a_n-(n-1)}\ge a_{n+1}-(n-1) for n=1,2,…,1994n=1,2,\ldots,1994, and 2a1995−1994≥a1+12\sqrt{a_{1995}-1994}\ge a_1+1.
Step 4 of 4: Recover and verify the unique sequence
xn=1⇒an=nx_n=1\Rightarrow a_n=n
Detailed analysis

From xn=1x_n=1 and xn=an−(n−1)x_n=a_n-(n-1), obtain an=na_n=n. Conversely, these values give 2an−(n−1)=2=an+1−(n−1)2\sqrt{a_n-(n-1)}=2=a_{n+1}-(n-1) for n=1,…,1994n=1,\ldots,1994, and 2a1995−1994=2=a1+12\sqrt{a_{1995}-1994}=2=a_1+1. Thus an=na_n=n is the unique solution.