MathLabs

Problem 4

Let CC be a circle of radius RR and center OO, and let SS be a fixed interior point. Let AA′AA' and BB′BB' be perpendicular chords through SS. The rectangles SAMBSAMB, SB′N′A′SB'N'A', SA′M′B′SA'M'B', and SBNASBNA are formed. Determine the locus of the four points M,N′,M′,NM,N',M',N as AA moves around CC.
Step 2 of 5: Relate the two perpendicular chords to the radius
AB2+A′B′2=4R2AB^2+A'B'^2=4R^2
Detailed analysis

Let DD be the second intersection of MN′MN' with CC. Equal inscribed angles give AD=ABAD=AB. Also DA′DA' is parallel to MN′MN', so the angle DA′B′DA'B' is right; therefore DD and B′B' are diametrically opposite. Thus A′D2+DB′2=4R2A'D^2+D B'^2=4R^2, and substituting AD=ABAD=AB yields AB2+A′B′2=4R2AB^2+A'B'^2=4R^2.