MathLabs

Problem 4

Let CC be a circle of radius RR and center OO, and let SS be a fixed interior point. Let AA′AA' and BB′BB' be perpendicular chords through SS. The rectangles SAMBSAMB, SB′N′A′SB'N'A', SA′M′B′SA'M'B', and SBNASBNA are formed. Determine the locus of the four points M,N′,M′,NM,N',M',N as AA moves around CC.
Step 3 of 5: Compute the constant sum of the two side squares
MN′2+M′N2=AB2+A′B′2+4SA⋅SA′=8R2−4OS2MN'^2+M'N^2=AB^2+A'B'^2+4SA\cdot SA'=8R^2-4OS^2
Detailed analysis

Expanding the squared side lengths of the two rectangles and using Pythagoras in the right triangles at SS gives MN′2+M′N2=AB2+A′B′2+4SA⋅SA′MN'^2+M'N^2=AB^2+A'B'^2+4SA\cdot SA'. The preceding step turns this into 8R2−4OS28R^2-4OS^2, which is independent of the position of AA.