MathLabs

Problem 4

Let CC be a circle of radius RR and center OO, and let SS be a fixed interior point. Let AA′AA' and BB′BB' be perpendicular chords through SS. The rectangles SAMBSAMB, SB′N′A′SB'N'A', SA′M′B′SA'M'B', and SBNASBNA are formed. Determine the locus of the four points M,N′,M′,NM,N',M',N as AA moves around CC.
Step 4 of 5: Convert the constant sum into a fixed radius
MN′2+M′N2=MM′2=4OM2MN'^2+M'N^2=MM'^2=4OM^2
Detailed analysis

Since MN′M′NMN'M'N is a rectangle, its diagonals are equal and perpendicular, so the sum of the squares of two adjacent sides is MM′2MM'^2. Since OO is its center, MM′=2OMMM'=2OM, hence MN′2+M′N2=4OM2MN'^2+M'N^2=4OM^2. Comparing with the previous step shows OMOM is constant.