MathLabs

Problem 1

Let ABCDABCD be a quadrilateral with AB=BC=CD=DAAB=BC=CD=DA. Let MNMN and PQPQ be segments perpendicular to diagonal BDBD, with M∈ADM\in AD, N∈DCN\in DC, P∈ABP\in AB, and Q∈BCQ\in BC, and with distance d>BD/2d>BD/2 between them. Show that the perimeter of hexagon AMNCQPAMNCQP does not depend on the positions of MNMN and PQPQ while their distance remains dd.
Step 5 of 5: Conclude independence from the positions
L=2AC+2AB−AChdL=2AC+\frac{2AB-AC}{h}d
Detailed analysis

Because t−s=dt-s=d is fixed, the final expression L=2AC+((2AB−AC)/h)dL=2AC+((2AB-AC)/h)d is constant. Therefore the perimeter of AMNCQPAMNCQP does not depend on the individual positions of MNMN and PQPQ.