MathLabs

Problem 4

Let P1P_1 and P3P_3 be fixed points. Let P2P_2 lie on the line through P3P_3 perpendicular to P1P3P_1P_3. Define Pn+1P_{n+1} as the foot of the perpendicular from PnP_n to Pn−1Pn−2P_{n-1}P_{n-2}. Show that the sequence converges to a point PP, and determine the locus of PP as P2P_2 varies.
Step 2 of 5: Use the first similarity
P5P4P6∼P1P2P3,P4P5∥P1P2P_5P_4P_6\sim P_1P_2P_3,\qquad P_4P_5\parallel P_1P_2
Detailed analysis

The triangle P5P4P6P_5P_4P_6 is similar, in that vertex order, to P1P2P3P_1P_2P_3. Since P4P5∥P1P2P_4P_5\parallel P_1P_2, the similarity is a half-turn about PP. Hence P1,P,P5P_1,P,P_5 are collinear.