MathLabs

Problem 4

Let P1P_1 and P3P_3 be fixed points. Let P2P_2 lie on the line through P3P_3 perpendicular to P1P3P_1P_3. Define Pn+1P_{n+1} as the foot of the perpendicular from PnP_n to Pn−1Pn−2P_{n-1}P_{n-2}. Show that the sequence converges to a point PP, and determine the locus of PP as P2P_2 varies.
Step 5 of 5: Describe the locus arc
∠XP1Y=2tan⁡−1(1/2),∠XOY=4tan⁡−1(1/2)\angle XP_1Y=2\tan^{-1}(1/2),\qquad\angle XOY=4\tan^{-1}(1/2)
Detailed analysis

Therefore the locus is the arc XP3YXP_3Y of the circle with diameter P1P3P_1P_3, with XP3=YP3XP_3=YP_3 and ∠XP1Y=2tan⁡−1(1/2)\angle XP_1Y=2\tan^{-1}(1/2). If OO is the midpoint of P1P3P_1P_3, its central angle is ∠XOY=4tan⁡−1(1/2)\angle XOY=4\tan^{-1}(1/2).