MathLabs

Problem 2

Show that (36a+b)(a+36b)(36a+b)(a+36b) cannot be a power of 22 for any positive integers aa and bb.
Step 1 of 4: Assume a counterexample
(36a+b)(a+36b)=2r(36a+b)(a+36b)=2^r
Detailed analysis

Suppose a counterexample exists and, after exchanging a,ba,b if necessary, choose one with a≤ba\le b and minimal aa. Since both factors are positive integers and their product is 2r2^r, each factor is a power of 22.