MathLabs

Problem 1

Compute the sum S=∑i=0101xi31−3xi+3xi2S = \sum_{i=0}^{101} \frac{x_i^3}{1 - 3x_i + 3x_i^2} for xi=i101x_i = \frac{i}{101}.
Step 1 of 4: Identify the complementary relationship between terms
In plain words

The points xix_i divide the interval [0,1][0, 1] into 101101 equal parts, so reflecting across the midpoint 12\frac{1}{2} pairs xix_i with 1−xi=x101−i1 - x_i = x_{101-i}.

x101−i=101−i101=1−i101=1−xix_{101-i} = \frac{101-i}{101} = 1 - \frac{i}{101} = 1 - x_i
Detailed analysis

For each index i∈{0,1,…,101}i \in \{0, 1, \ldots, 101\}, the reflected index 101−i101 - i also lies in {0,1,…,101}\{0, 1, \ldots, 101\}, and the corresponding nodes satisfy x101−i=101−i101=1−xix_{101-i} = \frac{101-i}{101} = 1 - x_i.