MathLabs

Problem 3

Let ABCABC be an equilateral triangle. Let PP be a point on ACAC and QQ a point on ABAB so that triangles ABPABP and ACQACQ are acute. Let RR and SS be the orthocentres of triangles ABPABP and ACQACQ, respectively. Let TT be the common point of the segments BPBP and CQCQ. Find all possible values of ∠CBP\angle CBP and ∠BCQ\angle BCQ such that triangle TRSTRS is equilateral.
Step 7 of 8: Solve the equal-angle equation
α=β,∠TAR=∠TBR  ⟹  ∠TAR=∠TBR=15∘.\alpha=\beta,\qquad \angle TAR=\angle TBR\implies \angle TAR=\angle TBR=15^\circ.
Detailed analysis

The equality alpha=beta makes the two displayed angles equal by the same symmetry. Their sum is 30 degrees, so each is 15 degrees; these are exactly alpha and beta in the original configuration.