MathLabs

Problem 2

Suppose ABCDABCD is a square of side length aa. Two parallel lines ℓ1\ell_1 and ℓ2\ell_2 in the plane are aa units apart. The square is placed so that ABAB and ADAD meet ℓ1\ell_1 at EE and FF, while CBCB and CDCD meet ℓ2\ell_2 at GG and HH. If the perimeters of △AEF\triangle AEF and △CGH\triangle CGH are m1m_1 and m2m_2, prove that m1+m2m_1+m_2 is constant, regardless of the placement.
Step 3 of 4: Express the bases by equal tangent lengths
EF=EM+FQ,GH=GN+HPEF=EM+FQ,\qquad GH=GN+HP
Detailed analysis

From equal tangent lengths from each external point to an excircle, EF=EM+FQEF=EM+FQ and GH=GN+HPGH=GN+HP. Therefore m1=AE+AF+EF=(AM+AQ)+(EM+FQ)=OM+OQm_1=AE+AF+EF=(AM+AQ)+(EM+FQ)=OM+OQ, while m2=CG+CH+GH=ON+OPm_2=CG+CH+GH=ON+OP.