MathLabs

Problem 3

Prove that there exists a triangle which can be cut into 2005 congruent triangles.
Step 4 of 5: Subdivide the second similar triangle
BCK⟶222 congruent trianglesBCK\longrightarrow22^2\text{ congruent triangles}
Detailed analysis

Apply the same construction to BCK using its corresponding side of length 22, producing 22 squared congruent triangles. Because ABK and BCK are similar, the pieces in both subdivisions have the same shape and size.