MathLabs

Problem 4

Let A,BA,B be distinct points on a given circle OO, and let PP be the midpoint of ABAB. Let O1O_1 be the circle tangent to the line ABAB at PP and tangent to OO. Let ℓ\ell, different from ABAB, be the tangent to O1O_1 through AA, and let CC be the intersection point other than AA of ℓ\ell and OO. Let QQ be the midpoint of BCBC, and let O2O_2 be the circle tangent to the line BCBC at QQ and tangent to the line segment ACAC. Prove that O2O_2 is tangent to OO.
Step 5 of 5: Identify the center and tangency point
NY⊥AC,NY=NQ=NA′,N is the center of O2NY\perp AC,\quad NY=NQ=NA',\quad N\text{ is the center of }O_2
Detailed analysis

Let YY be the tangency point of O2O_2 with ACAC. Since N,C,TN,C,T are collinear, the angle relations in the construction give ∠ACN=∠ACT=∠BCT=∠QCN\angle ACN=\angle ACT=\angle BCT=\angle QCN. Also CY=CQCY=CQ because the two segments are tangents from C to O2O_2. Thus triangles YCNYCN and QCNQCN are congruent, so NY⊥ACNY\perp AC and NY=NQ=NA′NY=NQ=NA'. Hence N is the center of O2O_2. Finally, O,A′,QO,A',Q lie on the perpendicular bisector of BCBC, and A′A' lies on both circles; the line of centers passes through A′A', proving that O2O_2 is tangent to OO at A′A'.