Problem 3
Find all positive integers such that for any integer there exists an integer for which is divisible by .
Step 1 of 4: Powers of three work
Detailed analysis
For modulus three to a positive power, suppose the two values coincide. The displayed factorization holds, and the second factor is never divisible by three, as a direct check modulo three shows. Hence a and b are congruent, so the map is injective on a finite residue system and therefore a permutation. Modulus one also works.