MathLabs

Problem 4

Call a rational number rr powerful if rr can be expressed in the form pkq\dfrac{p^k}{q} for some relatively prime positive integers p,qp,q and some integer k>1k>1. Let a,b,ca,b,c be positive rational numbers such that abc=1abc=1. Suppose there exist positive integers x,y,zx,y,z such that ax+by+cza^x+b^y+c^z is an integer. Prove that a,b,ca,b,c are all powerful.
Step 2 of 5: Deduce a1z∣b2y+za_1^z\mid b_2^{y+z}
a1z∣b1x+zb2y+z,gcd⁡(a1,b1)=1  ⟹  a1z∣b2y+za_1^z\mid b_1^{x+z}b_2^{y+z},\quad \gcd(a_1,b_1)=1 \implies a_1^z\mid b_2^{y+z}
Detailed analysis

The left side of the divisibility above is divisible by a1za_1^z, and a1za_1^z clearly divides the first two terms on the right (each already contains a factor a1za_1^z); hence a1za_1^z divides the third term b1x+zb2y+zb_1^{x+z}b_2^{y+z}. Since gcd⁡(a1,b1)=1\gcd(a_1,b_1)=1, this forces a1z∣b2y+za_1^z\mid b_2^{y+z}.