MathLabs

Problem 2

Let f(x)f(x) and g(x)g(x) be given by f(x)=1x+1x−2+1x−4+⋯+1x−2018f(x)=\dfrac1x+\dfrac1{x-2}+\dfrac1{x-4}+\cdots+\dfrac1{x-2018} and g(x)=1x−1+1x−3+1x−5+⋯+1x−2017g(x)=\dfrac1{x-1}+\dfrac1{x-3}+\dfrac1{x-5}+\cdots+\dfrac1{x-2017}. Prove that ∣f(x)−g(x)∣>2|f(x)-g(x)|>2 for any non-integer real number xx satisfying 0<x<20180<x<2018.
Step 1 of 6: Write f and g as sums
f(x)=∑k=010091x−2k,g(x)=∑k=010081x−(2k+1)f(x)=\sum_{k=0}^{1009}\frac1{x-2k},\qquad g(x)=\sum_{k=0}^{1008}\frac1{x-(2k+1)}
Detailed analysis

The function ff sums 10101010 terms with even shifts 0,2,…,20180,2,\dots,2018, and gg sums 10091009 terms with odd shifts 1,3,…,20171,3,\dots,2017. Both are undefined exactly at the integers 0,1,…,20180,1,\dots,2018, which are excluded by hypothesis.