MathLabs

Problem 5

Find all polynomials P(x)P(x) with integer coefficients such that for all real numbers ss and tt, if P(s)P(s) and P(t)P(t) are both integers, then P(st)P(st) is also an integer.
Step 8 of 8: Undo the normalization and verify the converse
P(x)=xn+k or P(x)=−xn+k(n≥0 integer, k∈Z)P(x)=x^n+k\ \text{or}\ P(x)=-x^n+k\quad(n\ge0\text{ integer},\ k\in\mathbb Z)
Detailed analysis

Steps 1–6 show the normalized polynomial is xnx^n, so undoing the sign and shift of step 1 gives P(x)=±xn+kP(x)=\pm x^n+k for some integer n≥0n\ge0 and integer kk. Conversely, if P(x)=±xn+kP(x)=\pm x^n+k and P(s),P(t)P(s),P(t) are integers then sn,tns^n,t^n are integers, so (st)n=sntn(st)^n=s^nt^n is an integer and P(st)=±(st)n+kP(st)=\pm(st)^n+k is an integer. Hence these are exactly the polynomials with the required property.