MathLabs

Problem 3

Let ABCABC be a scalene triangle with circumcircle Ω\Omega. Let MM be the midpoint of BCBC. A variable point PP is selected on segment AMAM. The circumcircles of triangles BPMBPM and CPMCPM meet Ω\Omega again at points DD and EE, respectively. The lines DPDP and EPEP meet the circumcircles of triangles CPMCPM and BPMBPM again at points XX and YY, respectively. Prove that, as PP varies, the circumcircle of triangle AXYAXY passes through a fixed point TT distinct from AA.
Step 1 of 9: Locate the first radical center on line AM
N=radical center of Ω, ⊙(BPM), ⊙(CPM) ⟹ BD, CE, PM concur at N,N∈AMN=\text{radical center of }\Omega,\ \odot(BPM),\ \odot(CPM)\ \Longrightarrow\ BD,\ CE,\ PM\ \text{concur at}\ N,\quad N\in AM
Detailed analysis

Let NN be the radical center of Ω\Omega, ⊙(BPM)\odot(BPM), and ⊙(CPM)\odot(CPM). The pairwise radical axes are BDBD (common points of Ω,⊙(BPM)\Omega,\odot(BPM)), CECE (common points of Ω,⊙(CPM)\Omega,\odot(CPM)), and PMPM (common points of ⊙(BPM),⊙(CPM)\odot(BPM),\odot(CPM)), so these three lines concur at NN. Since PP and MM both lie on segment AMAM, line PMPM is exactly line AMAM, so N∈AMN\in AM.