MathLabs

Asian Pacific Mathematics Olympiad · 2023

Problems

  1. Problem 1Let n≥5n\ge5 be an integer. Consider nn squares with side lengths 1,2,…,n1,2,\ldots,n, respectively. The squares are arranged in the plane with their sides parallel to the xx and yy axes. Suppose that no two squares touch, except possibly at their vertices. Show that it is possible to arrange these squares in a way such that every square touches exactly two other squares.Solutions: 1
  2. Problem 2Find all integers nn satisfying n≥2n\ge2 and σ(n)p(n)−1=n,\frac{\sigma(n)}{p(n)-1}=n, in which σ(n)\sigma(n) denotes the sum of all positive divisors of nn, and p(n)p(n) denotes the largest prime divisor of nn.Solutions: 1
  3. Problem 3Let ABCDABCD be a parallelogram. Let WW, XX, YY, and ZZ be points on sides ABAB, BCBC, CDCD, and DADA, respectively, such that the incenters of triangles AWZAWZ, BXWBXW, CYXCYX, and DZYDZY form a parallelogram. Prove that WXYZWXYZ is a parallelogram.Solutions: 1
  4. Problem 4Let c>0c>0 be a given positive real and R>0\mathbb{R}_{>0} be the set of all positive reals. Find all functions f:R>0→R>0f:\mathbb{R}_{>0}\to\mathbb{R}_{>0} such that f((c+1)x+f(y))=f(x+2y)+2cxfor all x,y∈R>0.f((c+1)x+f(y))=f(x+2y)+2cx\quad\text{for all }x,y\in\mathbb{R}_{>0}.Solutions: 1
  5. Problem 5There are nn line segments on the plane, no three intersecting at a point, and each pair intersecting once in their respective interiors. Tony and his 2n−12n-1 friends each stand at a distinct endpoint of a line segment. Tony wishes to send Christmas presents to each of his friends as follows: First, he chooses an endpoint of each segment as a "sink". Then he places the present at the endpoint of the segment he is at. The present moves as follows: if it is on a line segment, it moves towards the sink; when it reaches an intersection of two segments, it changes the line segment it travels on and starts moving towards the new sink. If the present reaches an endpoint, the friend on that endpoint can receive their present. Prove that Tony can send presents to exactly nn of his 2n−12n-1 friends.Solutions: 1