MathLabs

Problem 5

Consider an infinite sequence a1,a2,…a_1,a_2,\ldots of positive integers such that 100!(am+am+1+⋯+an)100!(a_m+a_{m+1}+\cdots+a_n) is a multiple of an−m+1an+ma_{n-m+1}a_{n+m} for all positive integers m,nm,n with m≤nm\le n. Prove that the sequence is either bounded or linear. A sequence is bounded if there is a constant NN such that an<Na_n<N for every positive integer nn, and it is linear if an=n⋅a1a_n=n\cdot a_1 for every positive integer nn.
Step 6 of 10: The preceding terms are unbounded
akd=kt⟹akd−1 is unboundeda_{kd}=kt\Longrightarrow a_{kd-1}\text{ is unbounded}
Detailed analysis

From Step 5, akd=kta_{kd}=kt tends to infinity. But akd=a1+(kd−1)a_{kd}=a_{1+(kd-1)} divides c(a1+akd−1)c(a_1+a_{kd-1}) by Step 1, so akd−1a_{kd-1} is unbounded as kk varies.