MathLabs

Problem 2

Let n≥2n \ge 2 be an integer. Let A1,A2,…,A2nA_1, A_2, \dots, A_{2^n} be the 2n2^n subsets of an nn-element set, listed in some order. Prove that ∣A1∖A2∣+∣A2∖A3∣+⋯+∣A2n−1∖A2n∣+∣A2n∖A1∣≥2n−2.|A_1\setminus A_2| + |A_2\setminus A_3| + \cdots + |A_{2^n-1}\setminus A_{2^n}| + |A_{2^n}\setminus A_1| \ge 2^{n-2}.
Step 3 of 5: Rewrite the target sum
∑x(ax+bx)=2∑xax  ⟹  ∑i∣Ai∖Ai+1∣=12∑x(ax+bx)\sum_x(a_x+b_x)=2\sum_x a_x \implies \sum_i|A_i\setminus A_{i+1}|=\tfrac12\sum_x(a_x+b_x)
Detailed analysis

Summing ax=bxa_x=b_x over all elements gives ∑xax=∑xbx\sum_xa_x=\sum_xb_x, so the required sum is half of ∑x(ax+bx)\sum_x(a_x+b_x).