Problem 5
An arbitrary point is selected in the interior of segment . Squares and are constructed on the same side of , with circumcenters and . Their circumcircles meet again at . Let be the intersection of and . (a) Prove . (b) Prove that passes through a fixed point independent of . (c) Find the locus of the midpoint of as varies.
Step 5 of 5: Compute the locus of the square-center midpoint
Detailed analysis
The centers and lie at distances and from , respectively, on the same side. Thus the midpoint has distance from . As varies, its projection along varies over the corresponding interval, so the locus is the segment on the line parallel to at distance (between the endpoint positions obtained as approaches and ).