MathLabs

Problem 5

An arbitrary point MM is selected in the interior of segment ABAB. Squares AMCDAMCD and MBEFMBEF are constructed on the same side of ABAB, with circumcenters PP and QQ. Their circumcircles meet again at NN. Let N′N' be the intersection of AFAF and BCBC. (a) Prove N=N′N=N'. (b) Prove that MNMN passes through a fixed point independent of MM. (c) Find the locus of the midpoint of PQPQ as MM varies.
Step 5 of 5: Compute the locus of the square-center midpoint
R=mid⁡(PQ)⟹d(R,AB)=AB4R=\operatorname{mid}(PQ)\quad\Longrightarrow\quad d(R,AB)=\frac{AB}{4}
Detailed analysis

The centers PP and QQ lie at distances AM/2AM/2 and MB/2MB/2 from ABAB, respectively, on the same side. Thus the midpoint RR has distance (AM/2+MB/2)/2=AB/4(AM/2+MB/2)/2=AB/4 from ABAB. As MM varies, its projection along ABAB varies over the corresponding interval, so the locus is the segment on the line parallel to ABAB at distance AB/4AB/4 (between the endpoint positions obtained as MM approaches AA and BB).