MathLabs

Problem 3

Solve the equation cos⁡nx−sin⁡nx=1\cos^n x-\sin^n x=1, where nn is a given positive integer.
Step 4 of 6: Exclude the third quadrant
x∈(π,3π/2):cos⁡nx−sin⁡nx=(−∣cos⁡x∣)n−(−∣sin⁡x∣)n<1x\in(\pi,3\pi/2):\quad \cos^n x-\sin^n x=(-\lvert\cos x\rvert)^n-(-\lvert\sin x\rvert)^n<1
Detailed analysis

Here both sine and cosine are negative. Put u=∣sin⁡x∣u=|\sin x| and v=∣cos⁡x∣v=|\cos x|, so u,v∈(0,1)u,v\in(0,1) and u2+v2=1u^2+v^2=1. For odd nn, the expression is un−vn<un<1u^n-v^n<u^n<1, so no point in this open interval solves the equation. The endpoint x=3π/2x=3\pi/2 gives equality.