MathLabs

Problem 3

Solve the equation cos⁡nx−sin⁡nx=1\cos^n x-\sin^n x=1, where nn is a given positive integer.
Step 5 of 6: Exclude the fourth quadrant interior
x∈(3π/2,2π):cos⁡nx−sin⁡nx=cos⁡nx+∣sin⁡x∣n<1x\in(3\pi/2,2\pi):\quad \cos^n x-\sin^n x=\cos^n x+|\sin x|^n<1
Detailed analysis

In this interval put u=cos⁡xu=\cos x and v=∣sin⁡x∣v=|\sin x|; both lie in (0,1)(0,1) and u2+v2=1u^2+v^2=1. For n=1n=1, u+v>1u+v>1 in the interior. For odd n≥3n\ge3, un+vn<u2+v2=1u^n+v^n<u^2+v^2=1. Thus the only endpoint solution here is x=3π/2x=3\pi/2 (while x=2πx=2\pi is the same as 00 modulo 2π2\pi).