MathLabs

Problem 5

Construct a triangle ABCABC if AC=bAC=b, AB=cAB=c, and ∠AMB=ω\angle AMB=\omega with ω<90∘\omega<90^\circ, where MM is the midpoint of BCBC. Prove that the construction has a solution if and only if btan⁡(ω/2)≤c<bb\tan(\omega/2)\le c<b. In what case does equality hold?
Step 3 of 6: Intersect with the prescribed-radius circle
C∈⊙(A,b)∩(major arc BD),AC=bC\in\odot(A,b)\cap\text{(major arc }BD\text{)},\qquad AC=b
Detailed analysis

Draw the circle centered at AA with radius bb. Choose an intersection CC of this circle with the major arc BDBD, and let MM be the midpoint of BCBC. In triangle BCDBCD, the points AA and MM are the midpoints of BDBD and BCBC, so AM∥CDAM\parallel CD; hence ∠AMB=∠DCB=ω\angle AMB=\angle DCB=\omega. Also AC=bAC=b is automatic.