MathLabs

Problem 2

Given a point AA and a segment BCBC, determine the locus of all points PP in space for which ∠APX=90∘\angle APX=90^\circ for some point XX on the segment BCBC.
Step 1 of 4: Parametrize the segment
In plain words

As XX slides along the segment, the perpendicularity expression changes linearly.

X=(1−t)B+tC,0≤t≤1,(A−P)⋅(X−P)=0X=(1-t)B+tC,\quad 0\le t\le1,\quad (A-P)\cdot(X-P)=0
Detailed analysis

The right angle at PP is equivalent to perpendicular vectors A−PA-P and X−PX-P. Write every point of BCBC as X=(1−t)B+tCX=(1-t)B+tC with 0≤t≤10\le t\le1.