MathLabs

Problem 4

Find all real solutions x1,…,x5x_1,\ldots,x_5 of xi+xi+2=yxi+1x_i+x_{i+2}=yx_{i+1} for i=1,…,5i=1,\ldots,5, where subscripts are reduced modulo 55.
Step 4 of 4: Classify the golden-ratio cases
In plain words

The exceptional quadratic values give a two-dimensional cyclic eigenspace; the uniform value gives a one-dimensional one.

y2+y−1=0⟹(x1,…,x5)=(s,t,yt−s,−y(s+t),ys−t)y^2+y-1=0\Longrightarrow (x_1,\ldots,x_5)=(s,t,yt-s,-y(s+t),ys-t)
Detailed analysis

For y=(−1±5)/2y=(-1\pm\sqrt5)/2, any s,t∈Rs,t\in\mathbb R produce a solution through the displayed two-parameter family. For y=2y=2, the solutions are precisely (s,s,s,s,s)(s,s,s,s,s). For every other real yy, only (0,0,0,0,0)(0,0,0,0,0) remains.