MathLabs

Problem 3

Given tetrahedron ABCDABCD, let opposite edges ABAB and CDCD have lengths aa and bb. Their skew-line distance is dd and their angle is θ\theta. A plane parallel to both ABAB and CDCD divides the tetrahedron into two solids. The ratio of the plane's distances from ABAB and CDCD is kk. Compute the ratio of the volumes of the two solids.
Step 3 of 5: Compute the prism-like solid
VWXPBYZ=3k2(k+1)3V.V_{WXPBYZ}=\frac{3k^2}{(k+1)^3}V.
Detailed analysis

The base triangle BYZBYZ is similar to BCDBCD with area scale k2/(k+1)2k^2/(k+1)^2. Its prism height is 1/(k+1)1/(k+1) of the altitude from AA to BCDBCD. Since V=Bh/3V=Bh/3, this gives VWXPBYZ=3k2V/(k+1)3V_{WXPBYZ}=3k^2V/(k+1)^3.