MathLabs

Problem 5

Let △OAB\triangle OAB have acute angle AOBAOB. Through a point M≠OM\ne O, draw perpendiculars to OAOA and OBOB, with feet PP and QQ. Let HH be the orthocenter of △OPQ\triangle OPQ. Find the locus of HH when MM ranges over (a) the side ABAB; (b) the interior of △OAB\triangle OAB.
Step 1 of 4: Set up the fixed feet
In plain words

The moving perpendiculars are parallel copies of two fixed altitudes.

BXperpOA,quadAYperpOB,quadMPparallelBX,quadMQparallelAY.BX\\perp OA,\\quad AY\\perp OB,\\quad MP\\parallel BX,\\quad MQ\\parallel AY.
Detailed analysis

Let XX be the foot from BB to OAOA, and YY the foot from AA to OBOB. Since MPperpOAMP\\perp OA and MQperpOBMQ\\perp OB, we have MPparallelBXMP\\parallel BX and MQparallelAYMQ\\parallel AY.