MathLabs

International Mathematical Olympiad · 1966

Problems

  1. Problem 1Three problems AA, BB, and CC were given on a mathematics olympiad. All 25 students solved at least one of these problems. The number of students who solved BB and not AA is twice the number of students who solved CC and not AA. The number of students who solved only AA is greater by 1 than the number of students who, along with AA, solved at least one other problem. Among the students who solved only one problem, half solved AA. How many students solved only BB?Solutions: 1
  2. Problem 2If aa, bb, and cc are the sides and α\alpha, β\beta, and γ\gamma are the respective angles of a triangle for which a+b=tan⁡γ2(atan⁡α+btan⁡β)a+b=\tan\frac{\gamma}{2}\left(a\tan\alpha+b\tan\beta\right), prove that the triangle is isosceles.Solutions: 1
  3. Problem 3Prove that the sum of the distances of the vertices of a regular tetrahedron from the center of its circumscribed sphere is less than the sum of the distances of these vertices from any other point in space.Solutions: 1
  4. Problem 4Prove the following equality for any natural number nn and any real number xx for which no denominator vanishes (that is, x≠kπ2tx\ne \frac{k\pi}{2^t} for t=0,1,…,nt=0,1,\dots,n and integer kk): 1sin⁡2x+1sin⁡4x+1sin⁡8x+⋯+1sin⁡2nx=cot⁡x−cot⁡2nx.\frac{1}{\sin 2x}+\frac{1}{\sin 4x}+\frac{1}{\sin 8x}+\cdots+\frac{1}{\sin 2^nx} = \cot x - \cot 2^nx.Solutions: 1
  5. Problem 5Solve the following system of equations for real numbers x1x_1, x2x_2, x3x_3, x4x_4: ∣a1−a2∣x2+∣a1−a3∣x3+∣a1−a4∣x4=1∣a2−a1∣x1+∣a2−a3∣x3+∣a2−a4∣x4=1∣a3−a1∣x1+∣a3−a2∣x2+∣a3−a4∣x4=1∣a4−a1∣x1+∣a4−a2∣x2+∣a4−a3∣x3=1\begin{aligned} |a_1-a_2|x_2 + |a_1-a_3|x_3 + |a_1-a_4|x_4 &= 1 \\ |a_2-a_1|x_1 + |a_2-a_3|x_3 + |a_2-a_4|x_4 &= 1 \\ |a_3-a_1|x_1 + |a_3-a_2|x_2 + |a_3-a_4|x_4 &= 1 \\ |a_4-a_1|x_1 + |a_4-a_2|x_2 + |a_4-a_3|x_3 &= 1 \end{aligned} where a1a_1, a2a_2, a3a_3, a4a_4 are mutually distinct real numbers.Solutions: 1
  6. Problem 6Let MM, KK, and LL be points chosen in the interiors of sides ABAB, BCBC, and CACA, respectively, of triangle ABCABC. Prove that the area of at least one of the three triangles △AML\triangle AML, △KBM\triangle KBM, and △LCK\triangle LCK is less than or equal to one-fourth of the area of triangle ABCABC.Solutions: 1