MathLabs

Problem 3

Let 1=a0≤a1≤a2≤⋯1=a_0\le a_1\le a_2\le\cdots be a sequence of real numbers. Define bn=∑k=1n(1−ak−1ak)1akb_n=\sum_{k=1}^n\left(1-\frac{a_{k-1}}{a_k}\right)\frac1{\sqrt{a_k}}. (a) Prove that 0≤bn<20\le b_n<2 for every nn. (b) Given any bb with 0≤b<20\le b<2, prove that there is such a sequence for which bn>bb_n>b for infinitely many nn.
Step 2 of 5: Interpret rectangles
In plain words

Rectangles under a decreasing curve give a visual meaning to every summand.

[Xk]=(ak−ak−1)ak−3/2[X_k]=(a_k-a_{k-1})a_k^{-3/2}
Six right-endpoint rectangles under f(x)=x−3/2f(x)=x^{-3/2}
Six rectangles illustrate the partial sum as area under $f(x)=x^{-3/2}$.
Detailed analysis

Take XkX_k with base [ak−1,ak][a_{k-1},a_k] and height ak−3/2a_k^{-3/2}. Since f(x)=x−3/2f(x)=x^{-3/2} decreases, XkX_k lies below the graph and the rectangles have disjoint interiors, so bnb_n is their total area.