MathLabs

Problem 3

Let 1=a0≤a1≤a2≤⋯1=a_0\le a_1\le a_2\le\cdots be a sequence of real numbers. Define bn=∑k=1n(1−ak−1ak)1akb_n=\sum_{k=1}^n\left(1-\frac{a_{k-1}}{a_k}\right)\frac1{\sqrt{a_k}}. (a) Prove that 0≤bn<20\le b_n<2 for every nn. (b) Given any bb with 0≤b<20\le b<2, prove that there is such a sequence for which bn>bb_n>b for infinitely many nn.
Step 4 of 5: Choose an arithmetic sequence
In plain words

Equal spacing turns the rectangles into the textbook Riemann sum.

ak=1+kDeltaxquad(Deltax>0)a_k=1+k\\Delta x\\quad(\\Delta x>0)
Detailed analysis

With ak=1+kΔxa_k=1+k\Delta x, bnb_n is the right-endpoint Riemann sum for ∫1anx−3/2dx\int_1^{a_n}x^{-3/2}dx; holding the endpoint fixed and taking Δx→0+\Delta x\to0^+ makes the sum converge to the integral.