MathLabs

Problem 2

Consider a convex polyhedron P1P_1 with nine vertices A1,A2,…,A9A_1,A_2,\ldots,A_9. Let PiP_i be obtained from P1P_1 by a translation that moves A1A_1 to AiA_i (i=2,3,…,9i=2,3,\ldots,9). Prove that at least two of P1,P2,…,P9P_1,P_2,\ldots,P_9 have an interior point in common.
Step 4 of 4: Compare volumes and force overlap
vol⁡(2P1)=23V=8V<9V=∑i=19vol⁡(Pi)\operatorname{vol}(2P_1)=2^3V=8V<9V=\sum_{i=1}^9\operatorname{vol}(P_i)
Detailed analysis

Let V=vol⁡(P1)>0V=\operatorname{vol}(P_1)>0. A factor-two dilation in three dimensions has volume 8V8V, whereas the nine translates have total volume 9V9V. If their interiors were pairwise disjoint, their union would have volume 9V9V (boundary overlaps have volume zero), yet it is contained in 2P12P_1 of volume 8V8V, a contradiction. Thus at least two have a common interior point.