MathLabs

Problem 6

Let A=(aij)A=(a_{ij}) (i,j=1,2,…,ni,j=1,2,\ldots,n) be a square matrix whose elements are nonnegative integers. Suppose that whenever aij=0a_{ij}=0, the sum of the elements in the iith row and the jjth column is at least nn. Prove that the sum of all elements of the matrix is at least n2/2n^2/2.
Step 7 of 7: Combine the block bounds
2S=2X+2Y+2Z≥(2X+Y)+Y+Z≥kn+k(n−k)+(n−k)2=n22S=2X+2Y+2Z\ge(2X+Y)+Y+Z\ge kn+k(n-k)+(n-k)^2=n^2
Detailed analysis

Finally, 2S=2X+2Y+2Z=(2X+Y)+Y+Z2S=2X+2Y+2Z=(2X+Y)+Y+Z. Applying the three bounds gives 2S≥kn+k(n−k)+(n−k)2=n22S\ge kn+k(n-k)+(n-k)^2=n^2, so S≥n2/2S\ge n^2/2.