MathLabs

Problem 6

Find all polynomials PP in two variables such that, for a positive integer nn, P(tx,ty)=tnP(x,y)P(tx,ty)=t^nP(x,y) for all real t,x,yt,x,y; for all real a,b,ca,b,c, P(b+c,a)+P(c+a,b)+P(a+b,c)=0P(b+c,a)+P(c+a,b)+P(a+b,c)=0; and P(1,0)=1P(1,0)=1.
Step 6 of 6: Verify the family and finish
P(x,y)=(x−2y)(x+y)n−1P(x,y)=(x-2y)(x+y)^{n-1}
Detailed analysis

This polynomial is homogeneous of degree nn and has P(1,0)=1P(1,0)=1. In the cyclic sum, put s=a+b+cs=a+b+c: each term equals (s−3a)sn−1(s-3a)s^{n-1}, (s−3b)sn−1(s-3b)s^{n-1}, or (s−3c)sn−1(s-3c)s^{n-1}; their sum is zero. Thus these, and only these, are the solutions.