MathLabs

Problem 3

A box whose shape is a rectangular parallelepiped can be completely filled with cubes of side 11. If one places inside it the maximum possible number of cubes, each of volume 22, with their sides parallel to those of the box, then exactly 40%40\% of the volume of the box is occupied. Determine the possible dimensions of all such boxes.
Step 4 of 6: Determine the first edge
In plain words

Ordering the three ratios lets us focus the largest one against the cube root of 55; checking only the small integers a=2,3,4a=2,3,4 by hand (larger ones being ruled out by the shrinking-bound argument) quickly forces the exact value.

a=2, ax=2a=2,\ \frac ax=2
Detailed analysis

Assume WLOG a/x≥b/y≥c/za/x\ge b/y\ge c/z, so a/x≥53a/x\ge\sqrt[3]5. If a≥4a\ge4 then x≥3x\ge3 and a/x<23(1+1/3)=23⋅43<53a/x<\sqrt[3]2(1+1/3)=\sqrt[3]2\cdot\frac43<\sqrt[3]5 (since 2⋅43<5⋅332\cdot4^3<5\cdot3^3), a contradiction; so a∈{2,3}a\in\{2,3\}. For a=3a=3, x=2x=2 and a/x=3/2<53a/x=3/2<\sqrt[3]5, also a contradiction. Hence a=2a=2, x=1x=1, and a/x=2a/x=2.