MathLabs

Problem 3

A box whose shape is a rectangular parallelepiped can be completely filled with cubes of side 11. If one places inside it the maximum possible number of cubes, each of volume 22, with their sides parallel to those of the box, then exactly 40%40\% of the volume of the box is occupied. Determine the possible dimensions of all such boxes.
Step 6 of 6: Determine the third edge and conclude
In plain words

By the third edge, the same three-step pattern (shrink the upper bound for large values, then hand-check the few small remaining candidates) has been applied once per edge, systematically exhausting all cases without missing any.

cz=32,c∈{3,6}\frac cz=\frac32,\qquad c\in\{3,6\}
Detailed analysis

Now c/z=5/2÷(5/3)=3/2c/z=5/2\div(5/3)=3/2. If c≥8c\ge8 then z≥6z\ge6 and c/z<23(1+1/6)<3/2c/z<\sqrt[3]2(1+1/6)<3/2 (since 2⋅73<33⋅632\cdot7^3<3^3\cdot6^3), a contradiction. Checking c=1,…,7c=1,\ldots,7 against c/z=3/2c/z=3/2 leaves exactly c=3c=3 (with z=2z=2) and c=6c=6 (with z=4z=4). Together with a=2,b=5a=2,b=5 from Steps 4–5, the only possible boxes are {a,b,c}={2,3,5}\{a,b,c\}=\{2,3,5\} and {2,5,6}\{2,5,6\} (up to permutation of the edges).