Problem 5
Consider the system of equations in unknowns , with every coefficient in . Prove that the system has a solution such that (a) all are integers; (b) at least one ; (c) for every .
Step 2 of 5: Bound one linear form
In plain words
Each row contributes only possible outputs, no matter how the coefficients are arranged.
Detailed analysis
For a fixed row , the linear form has maximum and minimum differing by at most : coefficients are in and each lies in . Thus takes at most integer values.