MathLabs

Problem 6

A sequence (un)(u_n) is defined by u0=2u_0=2, u1=52u_1=\frac52, and un+1=un(un−12−2)−u1u_{n+1}=u_n(u_{n-1}^2-2)-u_1 for n=1,2,…n=1,2,\ldots. Prove that for every positive integer nn, ⌊un⌋=22n−(−1)n3\lfloor u_n\rfloor=2^{\frac{2^n-(-1)^n}{3}}, where ⌊x⌋\lfloor x\rfloor denotes the greatest integer less than or equal to xx.
Step 3 of 6: Build the model sequence
In plain words

This is a “change of coordinates”: the nonlinear-looking recurrence for unu_n becomes linear addition in the exponent xnx_n.

an=2xn+2−xna_n=2^{x_n}+2^{-x_n}
Detailed analysis

Let an=2xn+2−xna_n=2^{x_n}+2^{-x_n}. The initial values match: a0=2=u0a_0=2=u_0 and a1=2+12=52=u1a_1=2+\frac12=\frac52=u_1. We will show that ana_n obeys the same recurrence as unu_n.