MathLabs

Problem 3

Two circles in a plane intersect. Let AA be one of their points of intersection. Starting simultaneously from AA, two points move with constant speeds, each travelling along its own circle in the same sense. The two points return to AA simultaneously after one revolution. Prove that there exists a fixed point PP in the plane such that, at any time, the distances from PP to the moving points are equal.
Step 2 of 5: Construct the fixed point
P=reflection of A in the perpendicular bisector of OO′P=\text{reflection of }A\text{ in the perpendicular bisector of }OO\prime
Detailed analysis

Reflect A across the perpendicular bisector of OO′ and call the image P. This point is fixed throughout the motion.