MathLabs

Problem 2

Let nn and rr be integers with 1≤r≤n1 \le r \le n, and consider all (nr)\binom{n}{r} subsets of rr elements of the set {1,2,…,n}\{1,2,\dots,n\}. Each such subset has a smallest element. Let F(n,r)F(n,r) denote the arithmetic mean of these smallest elements. Prove that F(n,r)=n+1r+1.F(n,r) = \frac{n+1}{r+1}.
Step 5 of 5: Simplify the binomial ratio
(n+1r+1)(nr)=(n+1)!(r+1)!(n−r)!n!r!(n−r)!=n+1r+1\frac{\binom{n+1}{r+1}}{\binom{n}{r}} = \frac{\frac{(n+1)!}{(r+1)!(n-r)!}}{\frac{n!}{r!(n-r)!}} = \frac{n+1}{r+1}
Detailed analysis

Expanding both binomial coefficients with factorials and cancelling n!/(n−r)!n!/(n-r)! and r!/(r+1)!=1/(r+1)r!/(r+1)!=1/(r+1) leaves exactly n+1r+1\frac{n+1}{r+1}, proving the claimed formula for F(n,r)F(n,r).