MathLabs

Problem 2

Let nn and rr be integers with 1≤r≤n1 \le r \le n, and consider all (nr)\binom{n}{r} subsets of rr elements of the set {1,2,…,n}\{1,2,\dots,n\}. Each such subset has a smallest element. Let F(n,r)F(n,r) denote the arithmetic mean of these smallest elements. Prove that F(n,r)=n+1r+1.F(n,r) = \frac{n+1}{r+1}.
Step 1 of 6: Count subsets with a fixed minimum
In plain words

This mirrors Step 1 of Solution 1 but sets up a different summation strategy afterward.

#{S:min⁡S=j}=(n−jr−1),j=1,…,n−r+1\#\{S : \min S = j\} = \binom{n-j}{r-1}, \quad j=1,\dots,n-r+1
Detailed analysis

If jj is the least element of an rr-subset, the remaining r−1r-1 elements come from the n−jn-j numbers larger than jj; there are (n−jr−1)\binom{n-j}{r-1} ways to choose them.