MathLabs

Problem 2

Let nn and rr be integers with 1≤r≤n1 \le r \le n, and consider all (nr)\binom{n}{r} subsets of rr elements of the set {1,2,…,n}\{1,2,\dots,n\}. Each such subset has a smallest element. Let F(n,r)F(n,r) denote the arithmetic mean of these smallest elements. Prove that F(n,r)=n+1r+1.F(n,r) = \frac{n+1}{r+1}.
Step 4 of 6: Apply the hockey-stick identity to each row
(n−ir−1)+(n−i−1r−1)+⋯+(r−1r−1)=(n−i+1r)\binom{n-i}{r-1}+\binom{n-i-1}{r-1}+\cdots+\binom{r-1}{r-1} = \binom{n-i+1}{r}
Detailed analysis

By the hockey-stick identity ∑k=r−1m(kr−1)=(m+1r)\sum_{k=r-1}^{m}\binom{k}{r-1}=\binom{m+1}{r}, each inner run collapses to a single binomial coefficient (n−i+1r)\binom{n-i+1}{r}.