MathLabs

Problem 2

Let nn and rr be integers with 1≤r≤n1 \le r \le n, and consider all (nr)\binom{n}{r} subsets of rr elements of the set {1,2,…,n}\{1,2,\dots,n\}. Each such subset has a smallest element. Let F(n,r)F(n,r) denote the arithmetic mean of these smallest elements. Prove that F(n,r)=n+1r+1.F(n,r) = \frac{n+1}{r+1}.
Step 6 of 6: Divide by the number of subsets
F(n,r)=(n+1r+1)(nr)=n+1r+1F(n,r) = \frac{\binom{n+1}{r+1}}{\binom{n}{r}} = \frac{n+1}{r+1}
Detailed analysis

Dividing the total (n+1r+1)\binom{n+1}{r+1} from Step 5 by the total number of subsets (nr)\binom{n}{r} gives the mean F(n,r)F(n,r), which simplifies to n+1r+1\frac{n+1}{r+1} exactly as in Solution 1.