MathLabs

Problem 4

(a) For which integers n>2n>2 does there exist a set of nn consecutive positive integers such that the largest number in the set divides the least common multiple of the remaining n−1n-1 numbers? (b) For which integers n>2n>2 is there exactly one such set?
Step 2 of 5: Invoke Bertrand's postulate
In plain words

Bertrand's postulate is the classic tool for guaranteeing a prime in a range roughly half as wide as the range itself — exactly what is needed to place a prime inside a window of nn consecutive integers.

n>5:∃ prime p with ⌊n2⌋<p<2⌊n2⌋, so p<n≤2pn>5: \exists \text{ prime } p \text{ with } \left\lfloor \tfrac n2 \right\rfloor < p < 2\left\lfloor \tfrac n2\right\rfloor, \text{ so } p<n\le 2p
Detailed analysis

Bertrand's postulate guarantees a prime strictly between ⌊n/2⌋\lfloor n/2\rfloor and 2⌊n/2⌋2\lfloor n/2\rfloor; rewriting the bounds shows this prime pp satisfies p<n≤2pp<n\le 2p.